document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161868>Question 161868</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The owner of a delicatessen mixed coffee that sold for $4.50 per pound with coffee that sold for $3.00 per pound. How many pounds of each were used to make 20 pounds of a blend that would sell for $3.90 per pound? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119287 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119287\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4.5X+3(20-X)=3.9*20<BR>\n" );
document.write( "4.5X+60-3X=78<BR>\n" );
document.write( "1.5X=78-60<BR>\n" );
document.write( "1.5X=18<BR>\n" );
document.write( "X=18/1.5<BR>\n" );
document.write( "X=12 POUNDS OF $4.50 COFFEE IS USED.<BR>\n" );
document.write( "20-12=8 POUNDS OF $3.00 COFFEE IS USED.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "4.5*12+3*8=78<BR>\n" );
document.write( "54+24=78<BR>\n" );
document.write( "78=78 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );