document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161867>Question 161867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triangle, one angle is 6 degrees more than the second angle. The third angle is 18 degrees more than the second angle. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119283 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119283\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=FIRST ANGLE.<BR>\n" );
document.write( "S=SECOND ANGLE.<BR>\n" );
document.write( "T=THIRD ANGLE.<BR>\n" );
document.write( "F=S+6<BR>\n" );
document.write( "T=S+18<BR>\n" );
document.write( "F+S+T=180<BR>\n" );
document.write( "(S+6)+S+(S+18)=180<BR>\n" );
document.write( "3S+24=180<BR>\n" );
document.write( "3S=180-24<BR>\n" );
document.write( "3X=156<BR>\n" );
document.write( "S=156/3<BR>\n" );
document.write( "S=52 DEGREES.<BR>\n" );
document.write( "F=52+6=58 DEGREES.<BR>\n" );
document.write( "T=52+18=70 DEGREES.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "52+58+70=180<BR>\n" );
document.write( "180=180\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );