document.write( "Question 161848: Bob is twice as old as Emma; Kent is 16 years older than Emma; the sum of their ages is 60 years; find the age of each.\r
\n" ); document.write( "\n" ); document.write( "Lets translate this into algebra\r
\n" ); document.write( "\n" ); document.write( "Your variables will be:
\n" ); document.write( "Bob = b
\n" ); document.write( "Emma= e
\n" ); document.write( "Kent= k\r
\n" ); document.write( "\n" ); document.write( "So\r
\n" ); document.write( "\n" ); document.write( "b = 2e
\n" ); document.write( "k = e + 16\r
\n" ); document.write( "\n" ); document.write( "b+e+k=60\r
\n" ); document.write( "\n" ); document.write( "you can only solve one equation if it only has one variable; so lets try to work with variable e only:
\n" ); document.write( "Since **b=2e and **k=e + 16 \r
\n" ); document.write( "\n" ); document.write( "then by substitution
\n" ); document.write( "b+e+k=60
\n" ); document.write( "(2e)+e + (e+16)=60
\n" ); document.write( "4e+16=60
\n" ); document.write( "4e=44
\n" ); document.write( "e=11\r
\n" ); document.write( "\n" ); document.write( "Then b=2e=2(11)=22
\n" ); document.write( "k=e+16=11+16=27\r
\n" ); document.write( "\n" ); document.write( "check:
\n" ); document.write( "b+e+k=11+22+37=60\r
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Algebra.Com's Answer #119267 by eperette(173)\"\" \"About 
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