document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161833>Question 161833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need some help please. \r<BR>\n" );
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document.write( "Juniors boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amount of time it takes to go 9 miles upstream, then what is the speed of the current?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119240 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 12/(15+c)=9/(15-c)<BR>\n" );
document.write( "9(15+c)=12(15-c)<BR>\n" );
document.write( "135+9c=180-12c<BR>\n" );
document.write( "9c+12c=180-135<BR>\n" );
document.write( "21c=45<BR>\n" );
document.write( "c=45/21<BR>\n" );
document.write( "c=2.143 mph is the current.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "12/(15+2.143)=9/(15-2.143)<BR>\n" );
document.write( "12/17.143=9/12.854<BR>\n" );
document.write( ".7~.7\r<BR>\n" );
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