document.write( "Question 161830: Find the length of the rectangle in terms of x.
\n" ); document.write( "Area = 4x^3-5x^2-10x-3 and width = 4x+3\r
\n" ); document.write( "\n" ); document.write( "Area of rectangle is L times W
\n" ); document.write( "This is the last problem for Algebra 1 course, your website helped me with all the other problems, but I can't solve this one. Thank you so much!
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Algebra.Com's Answer #119238 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
Area = 4x^3-5x^2-10x-3 and width = 4x+3
\n" ); document.write( "(4x^3-5x^2-10x-3)/(4x+3)=(x^2-2x-1) is the length.
\n" ); document.write( "This requires long division which is very clumbersome to present here.
\n" ); document.write( "Proof:
\n" ); document.write( "x^2-2x-1
\n" ); document.write( "4x+3 (multiply)
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\n" ); document.write( "4x^3-8x^2-4x+3x^2-6x-3
\n" ); document.write( "4x^3-5x^2-10x-3
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