document.write( "Question 161731: A man rowed 10 km up ariver in 5 hours and back in 21/2 hours. Find the rate of the current and his rate of rowing in still water. \n" ); document.write( "
Algebra.Com's Answer #119215 by josmiceli(19441)\"\" \"About 
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Let the rate of the current = \"c\"
\n" ); document.write( "Let his rate rowing in still water = \"s\"
\n" ); document.write( "Going upriver is against the current
\n" ); document.write( "\"10%2F%28s+-+c%29+=+5\"
\n" ); document.write( "Going back is with the current
\n" ); document.write( "\"10%2F%28s+%2B+c%29+=+2.5\"
\n" ); document.write( "This is 2 equations and 2 unknowns, so I should
\n" ); document.write( "be able to solve
\n" ); document.write( "Multiply both sides of the 1st by \"s+-+c\"
\n" ); document.write( "Multiply both sides of the 2nd by \"s+%2B+c\"
\n" ); document.write( "(1) \"10+=+5%2A%28s+-+c%29\"
\n" ); document.write( "(2) \"10+=+2.5%2A%28s+%2B+c%29\"
\n" ); document.write( "----------------------
\n" ); document.write( "(1) \"10+=+5s+-+5c\"
\n" ); document.write( "(2) \"10+=+2.5s+%2B+2.5c\"
\n" ); document.write( "Multiply (2) by \"2\" and add equations
\n" ); document.write( "(1) \"10+=+5s+-+5c\"
\n" ); document.write( "(2) \"20+=+5s+%2B+5c\"
\n" ); document.write( "\"30+=+10s\"
\n" ); document.write( "\"s+=+3\" km/hr
\n" ); document.write( "And, since
\n" ); document.write( "\"10%2F%28s+-+c%29+=+5\"
\n" ); document.write( "\"10%2F%283+-+c%29+=+5\"
\n" ); document.write( "\"10+=+5%2A%283+-+c%29\"
\n" ); document.write( "\"10+=+15+-+5c\"
\n" ); document.write( "\"5c+=+5\"
\n" ); document.write( "\"c+=+1\" km/hr
\n" ); document.write( "His rate in still water is 3 km/hr and the rate of the
\n" ); document.write( "current is 1 km/hr
\n" ); document.write( "check:
\n" ); document.write( "\"10%2F%28s+-+c%29+=+5\"
\n" ); document.write( "\"10%2F%283+-+1%29+=+5\"
\n" ); document.write( "\"10%2F2+=+5\"
\n" ); document.write( "\"5+=+5\"
\n" ); document.write( "OK
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