document.write( "Question 161736: a certain number, if two digits equals 4 times thew sum of its digits. the number made by reversing the order of the digits is 27 greater than the given number. what is the number? \n" ); document.write( "
Algebra.Com's Answer #119196 by Fombitz(32388)\"\" \"About 
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Let's call the number in the tens place A and the number in the ones place B.
\n" ); document.write( "The number would be AB or 10*A+B.
\n" ); document.write( "1.\"10A%2BB=4%2A%28A%2BB%29\"
\n" ); document.write( "If the number is reversed then,
\n" ); document.write( "2.\"10B%2BA=27%2B%2810A%2BB%29\"
\n" ); document.write( "Let's simplify both equations,
\n" ); document.write( "1.\"10A%2BB=4A%2B4B\"
\n" ); document.write( "1.\"6A-3B=0\"
\n" ); document.write( "and now eq. 2,
\n" ); document.write( "2.\"10B%2BA=27%2B%2810A%2BB%29\"
\n" ); document.write( "2.\"-9A%2B9B=27\"
\n" ); document.write( "Let's multiply eq. 1 by 3 and add to eq. 2,
\n" ); document.write( "then we can solve for A.
\n" ); document.write( "\"18A-9B%2B%28-9A%29%2B9B=0%2B27\"
\n" ); document.write( "\"9A=27\"
\n" ); document.write( "\"A=3\"
\n" ); document.write( "Now use eq. 1 to solve for B.
\n" ); document.write( "1.\"6A-3B=0\"
\n" ); document.write( "\"18-3B=0\"
\n" ); document.write( "\"-3B=-18\"
\n" ); document.write( "\"B=6\"
\n" ); document.write( "The original number is 36, the reversed order number is 63.
\n" ); document.write( "Check the answer.
\n" ); document.write( "36+27=63
\n" ); document.write( "63=63.
\n" ); document.write( "True statement.
\n" ); document.write( "Good answer.
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