document.write( "Question 161715:
\n" ); document.write( "Find the equation, in standard form, with all integer coefficients, of the line perpendicular to x-2y=24 and passing through (1,3). Thank you \n" ); document.write( "
Algebra.Com's Answer #119188 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
First, manipulate x-2y=24 into the \"slope-intercept\" form of the line:
\n" ); document.write( "y = mx+b
\n" ); document.write( "where
\n" ); document.write( "m is slope
\n" ); document.write( "b is y-intercept
\n" ); document.write( ".
\n" ); document.write( "x-2y=24
\n" ); document.write( "substracting x from both sides:
\n" ); document.write( "-2y=-x+24
\n" ); document.write( "dividing both sides by -2:
\n" ); document.write( "y = (1/2)x - 12
\n" ); document.write( "Slope of the line is 1/2
\n" ); document.write( ".
\n" ); document.write( "For our line to be perpendicular, the product of our slope and 1/2 has to be -1:
\n" ); document.write( "Let m = slope of our new line
\n" ); document.write( "then
\n" ); document.write( "(1/2)m = -1
\n" ); document.write( "m = -2
\n" ); document.write( ".
\n" ); document.write( "Recapping we now have the slope of our new line (-2) and a single point (1,3). Plug this all into the \"point-slope\" form:
\n" ); document.write( "y - y1 = m(x-x1)
\n" ); document.write( "y - 3 = -2(x-1)
\n" ); document.write( "y - 3 = -2x+2
\n" ); document.write( "y = -2x + 5 (this is what they're looking for)\r
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