document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161672>Question 161672</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Working on Chemistry homework. Could not understand this problem in class, still don't understand. \"The density of an antifreeze soltuion measured .78g/ml. The solution was a mixture of 40% water and 60% antifreeze compound. How many g of antifreeze compound are necessary to prepare 80.0 mL of antifreeze solution?\" I tried setting up my equation a couple different ways and I am sure I did not get the right answer. I got 104 g/Antifreeze. Please help me figure out how to set up this equation! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119164 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119164\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> total mass of solution is 80(.78) or 62.4g\r<BR>\n" );
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document.write( "BY VOLUME<BR>\n" );
document.write( "40% of 80 ml is 32 ml __ water is 1g/ml __ so 32g of water\r<BR>\n" );
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document.write( "62.4-32 or 30.4g of antifreeze\r<BR>\n" );
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document.write( "BY WEIGHT<BR>\n" );
document.write( "60% of 62.4 is 37.4g of antifreeze </SPAN>\n" );
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