document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161665>Question 161665</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the complement of an angle is 20 degrees less than half the supplement find the angle its complement and its supplement<BR>\n" );
document.write( "90-x=(180-x)/2 -20<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119150 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119150\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you have the formula right.<BR>\n" );
document.write( "all you have to do is solve it.<BR>\n" );
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document.write( "90 - x = (180-x)/2 - 20<BR>\n" );
document.write( "multiply both sides of equation by 2.<BR>\n" );
document.write( "180 - 2*x = 180 - x - 40<BR>\n" );
document.write( "subtract 180 from both sides and add 2*x to both sides and add 40 to both sides.<BR>\n" );
document.write( "equation becomes<BR>\n" );
document.write( "40 = x which is the same as x = 40.<BR>\n" );
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document.write( "complement of 40 is 50.<BR>\n" );
document.write( "supplement of 40 is 140.<BR>\n" );
document.write( "1/2 * 140 - 20 should equal 50.<BR>\n" );
document.write( "70 - 20 = 50<BR>\n" );
document.write( "it does.<BR>\n" );
document.write( "formula is good.<BR>\n" );
document.write( "angle equals 40 degrees.\r<BR>\n" );
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