document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161654>Question 161654</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangle has a perimeter of 161 miles. Each of the two smaller sides of the triangle is two thirds the length of of the longest side. Find the length of each side of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119146 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119146\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 161.<BR>\n" );
document.write( "L = larger side.<BR>\n" );
document.write( "2/3 * L = smaller side.<BR>\n" );
document.write( "P = L + 2*(2/3)*L = L + (4/3 * L) = L * (1 + 4/3) = L * (7/3) = (7/3)*L<BR>\n" );
document.write( "(7/3)*L = 161<BR>\n" );
document.write( "L = (3/7)*161<BR>\n" );
document.write( "L = 69<BR>\n" );
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document.write( "larger side = 69<BR>\n" );
document.write( "smaller side = 2/3 * 69 = 46<BR>\n" );
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document.write( "69 + 2*(46) = 69 + 92 = 161<BR>\n" );
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document.write( "sizes prove to be good.<BR>\n" );
document.write( "answer is:<BR>\n" );
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document.write( "larger side = 69<BR>\n" );
document.write( "smaller side = 46<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );