document.write( "Question 23220: I having a little difficulty in the following problems. I appreciate your help!\r
\n" ); document.write( "\n" ); document.write( "Solve the unknown variable:\r
\n" ); document.write( "\n" ); document.write( "1. 4(-1)(1-y)+8=0
\n" ); document.write( "2. 1-2(3-4)+y=-2y+8(1-1)
\n" ); document.write( "3. y/8=4+(y-2)/24
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #11914 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
1. 4(-1)(1-y)+8=0
\n" ); document.write( "-4(1-y) + 8 = 0
\n" ); document.write( "-4 + 4y + 8 = 0
\n" ); document.write( "4y + 4 = 0
\n" ); document.write( "4y = -4
\n" ); document.write( "y = -1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2. 1-2(3-4)+y=-2y+8(1-1)
\n" ); document.write( "Do parentheses first!
\n" ); document.write( "1-2(-1) + y = -2y + 8(0)
\n" ); document.write( "1+2 + y = -2y
\n" ); document.write( "3 + y -y = -2y -y
\n" ); document.write( "3 = -3y\r
\n" ); document.write( "\n" ); document.write( "Divide by -3:
\n" ); document.write( "y=-1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "3. \"y%2F8=4%2B%28y-2%29%2F24\"
\n" ); document.write( "Multiply both sides by the LCD which is 24:\r
\n" ); document.write( "\n" ); document.write( "\"24%2A+%28y%2F8%29=24%2A+4%2B+24%2A%28%28y-2%29%2F24%29\"
\n" ); document.write( "\"3y+=+96%2B+y+-2\"
\n" ); document.write( "\"3y+-y+=+94+%2By+-y\"
\n" ); document.write( "\"2y+=+94\"
\n" ); document.write( "\"y=47\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "R^2 at SCC
\n" ); document.write( "
\n" ); document.write( "
\n" );