document.write( "Question 161630: A mechanic has 20 liters of a 50% antifreeze solution. how many liters of pure antifreeze should be added to the antifreeze solution to make an antifreeze solution that is 75% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #119124 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .5*20+X=.75(20+X) \n" ); document.write( "10+X=15+.75X \n" ); document.write( "X-.75X=15-10 \n" ); document.write( ".25X=5 \n" ); document.write( "X=5/.25 \n" ); document.write( "X=20 LITERS OF PURE ANTIFREEZE IS USED. \n" ); document.write( "PROOF: \n" ); document.write( ".5*20+20=.75(20+20) \n" ); document.write( "10+20=.75*40 \n" ); document.write( "30=30\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |