document.write( "Question 161630: A mechanic has 20 liters of a 50% antifreeze solution. how many liters of pure antifreeze should be added to the antifreeze solution to make an antifreeze solution that is 75% antifreeze? \n" ); document.write( "
Algebra.Com's Answer #119124 by checkley77(12844)\"\" \"About 
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.5*20+X=.75(20+X)
\n" ); document.write( "10+X=15+.75X
\n" ); document.write( "X-.75X=15-10
\n" ); document.write( ".25X=5
\n" ); document.write( "X=5/.25
\n" ); document.write( "X=20 LITERS OF PURE ANTIFREEZE IS USED.
\n" ); document.write( "PROOF:
\n" ); document.write( ".5*20+20=.75(20+20)
\n" ); document.write( "10+20=.75*40
\n" ); document.write( "30=30\r
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