document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161650>Question 161650</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 174 feet, find the width and the length </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #119122 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=119122\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w = width of rectangle<BR>\n" );
document.write( "then because \"length of a rectangle is 3 feet less than twice the width\" we have<BR>\n" );
document.write( "2w-3 = length of rectangle<BR>\n" );
document.write( ".<BR>\n" );
document.write( "perimeter of any rectangle is:<BR>\n" );
document.write( "2(length+width)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "2(w + 2w-3) = 174<BR>\n" );
document.write( "2w + 4w - 6 = 174<BR>\n" );
document.write( "6w - 6 = 174<BR>\n" );
document.write( "6w = 180<BR>\n" );
document.write( "w = 30 feet (width)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "length:<BR>\n" );
document.write( "2w-3 = 2(30)-3 = 60-3 = 57 feet (length)<BR>\n" );
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