document.write( "Question 161625: At noon Tom leaves in his boat from a dock and heads south. He travels at a rate of 25 mph. Ten minutes later, Mary leaves the same dock in her speedboat and heads after Tom. If she travels at a rate of 30 miles per hour at what time will she catch up with Tom? \n" ); document.write( "

Algebra.Com's Answer #119104 by checkley77(12844) $\"\"$ $\"About$

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25T=30(T-1/6)
\n" ); document.write( "25T=30T-5
\n" ); document.write( "25T-30T=-5
\n" ); document.write( "-5T=-5
\n" ); document.write( "T=1 HOUR IS THE CATCH-UP TIME FOR MARY.
\n" ); document.write( "PROOF:
\n" ); document.write( "25*1=30(1-1/6)
\n" ); document.write( "25=30*5/6
\n" ); document.write( "25=150/6
\n" ); document.write( "25=25 MILES IS THE DISTANCE TRAVELED BEFORE THE CATCH-UP. \n" ); document.write( "

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