document.write( "Question 23211: inequality: 2b-12>_13 and 18<_ 6y-12
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Algebra.Com's Answer #11910 by rapaljer(4671) $\"\"$ $\"About$

You can put this solution on YOUR website!
Apparently these are two unrelated inequalities??\r
\n" ); document.write( "\n" ); document.write( " $\"2b-12+%3E=+13\"$
\n" ); document.write( " $\"2b-12%2B12+%3E=+13%2B12\"$
\n" ); document.write( " $\"2b%3E=+25\"$
\n" ); document.write( " $\"b%3E=+25%2F2\"$ or
\n" ); document.write( " $\"b%3E=+12.5\"$ \r
\n" ); document.write( "\n" ); document.write( "On the numberline locate the number 12.5, and shade from that point to the right. Do NOT include the endpoint!\r
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\n" ); document.write( "\n" ); document.write( " $\"18%3C=+6y+-12\"$
\n" ); document.write( " $\"18+-+6y+%3C=+6y-6y+-12\"$
\n" ); document.write( " $\"18-6y+%3C=+-12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"18-18+-6y+%3C=+-12-18\"$
\n" ); document.write( " $\"-6y+%3C=+-30\"$ \r
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\n" ); document.write( "\n" ); document.write( "Now, here is the key step. Whenever you multiply or divide both sides of an inequality by a negative number, you must REVERSE the inequality.
\n" ); document.write( " $\"-6y+%3C=+-30\"$
\n" ); document.write( " $\"%28-6y%29%2F-6+%3E=+%28-30%29%2F%28-6%29\"$
\n" ); document.write( " $\"+y+%3E=+5\"$ \r
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\n" ); document.write( "\n" ); document.write( "Locate the number 5 on the numberline, and shade everything to the right of 5, and also INCLUDE the 5. \r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( "

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