document.write( "Question 161526: given the algebraic relation x=y^2+1, determine the domain, range, and whether or not it is a funtion. on my graphing calculator it shows a line that starts at (-.851,.386)to infinity. it shows it as though if you did a vertical line test, it would be a function. I'm confused because if I insert a pos # into y or a - # into y, squaring it will give you the same number. you can't have 2 different y's giving the same x or it is not a function, right? \n" );
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Algebra.Com's Answer #119089 by Edwin McCravy(20056)  You can put this solution on YOUR website! given the algebraic relation x=y^2+1, determine the domain, range, and whether or not it is a funtion. \n" );
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document.write( "I think you are a little confused. Before you enter it in \r\n" );
document.write( "your calculator you must solve the equation for y:\r\n" );
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document.write( " =± \r\n" );
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document.write( "This means the equation consists of two function graphs,\r\n" );
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document.write( "One function graph is the graph of this function, using\r\n" );
document.write( "the positive square root:\r\n" );
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document.write( " = \r\n" );
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document.write( "The other function graph is the graph of this function,\r\n" );
document.write( "using the negative square root:\r\n" );
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document.write( "But the original equation\r\n" );
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document.write( "consiste of BOTH of these at the same time on the\r\n" );
document.write( "same set of axes, like this:\r\n" );
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document.write( "and this is not a function because it does not\r\n" );
document.write( "pass the vertical line test. It is a parabola\r\n" );
document.write( "that opens to the right.\r\n" );
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document.write( "Since the x-values of the graph start where x=1,\r\n" );
document.write( "including that point, and the graph goes to \r\n" );
document.write( "infinity on the right the domain is \r\n" );
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document.write( "Since the y-values go both upward and downward\r\n" );
document.write( "from 0 both to positive and negative infinity,\r\n" );
document.write( "the range is \r\n" );
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document.write( "No, it is not a function.\r\n" );
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document.write( "Edwin \r \n" );
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