document.write( "Question 161590: Find three consecutive odd integers such that the product of the first and second integer is 7 less then 10 times the third integer. \n" ); document.write( "

Algebra.Com's Answer #119069 by nerdybill(7384) $\"\"$ $\"About$

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Find three consecutive odd integers such that the product of the first and second integer is 7 less then 10 times the third integer.
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\n" ); document.write( "Let x = first consecutive odd integer
\n" ); document.write( "then
\n" ); document.write( "x+2 = second consecutive odd integer
\n" ); document.write( "x+4 = third consecutive odd integer
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\n" ); document.write( "From: \"product of the first and second integer is 7 less then 10 times the third integer\"
\n" ); document.write( "x(x+2) = 10(x+4) - 7
\n" ); document.write( "x^2 + 2x = 10x + 40 - 7
\n" ); document.write( "x^2 + 2x = 10x + 33
\n" ); document.write( "x^2 - 8x - 33 = 0
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\n" ); document.write( "Factoring gives us:
\n" ); document.write( "(x-11)(x+3) = 0
\n" ); document.write( "therefore,
\n" ); document.write( "x = {-3, 11}
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\n" ); document.write( "Two possible solutions:
\n" ); document.write( "11, 13, 15
\n" ); document.write( "-3, -1, 1
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