document.write( "Question 161585: A river is flowing at a rate of 5 km/h. A boat travels 12km upstream and 36km downstream in a total of 9hours. What is the speed of the boat in still water? \n" ); document.write( "
Algebra.Com's Answer #119061 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A river is flowing at a rate of 5 km/h. A boat travels 12km upstream and 36km downstream in a total of 9hours. What is the speed of the boat in still water? \n" ); document.write( "-------------------------- \n" ); document.write( "B = speed of boat \n" ); document.write( "B-5 = speed of boat upstream \n" ); document.write( "B+5 = speed downstream \n" ); document.write( "-------------------- \n" ); document.write( "h = hours going upstream \n" ); document.write( "h*(B-5) = 12 \n" ); document.write( "(9-h)*(B+5) = 36 \n" ); document.write( "--------------- \n" ); document.write( "B = 12/h + 5 \n" ); document.write( "B = 36/(9-h) - 5 \n" ); document.write( "B = 12/h + 5 = 36/(9-h) - 5 \n" ); document.write( "12/h + 10 = 36/(9-h) \n" ); document.write( "Multiply by h*(9-h) \n" ); document.write( "12(9-h) + 10h(9-h) = 36h \n" ); document.write( "108-12h + 90h-10h^2 = 36h \n" ); document.write( "Collect terms \n" ); document.write( "-10h^2 + 42h + 108 = 0 \n" ); document.write( "5h^2 - 21h - 54 = 0 \n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The online solver always uses x, so sub h for x. \n" ); document.write( "The -1.8 hours is not usable, so the time going upstream is, \n" ); document.write( "h = 6 hours. \n" ); document.write( "------------- \n" ); document.write( "Sub h into B = 12/h + 5 to solve for B \n" ); document.write( "B = 12/6 + 5 \n" ); document.write( "B = 7 kph \n" ); document.write( "------------- \n" ); document.write( "The people should have gotten out and walked, woulda been faster. \n" ); document.write( " \n" ); document.write( " |