document.write( "Question 161575: A sum of $2000 is split between two investments, one paying 7% interest and the other 8%. If the return on the 8% investment exceeds that of the 7% investment by $40 per year, how much is invested at each rate. \n" ); document.write( "

Algebra.Com's Answer #119049 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"x\"$ = amount invested @ 7%
\n" ); document.write( " $\"2000+-+x\"$ will be the amount invested @ 8%
\n" ); document.write( " $\".08%2A%282000+-+x%29+=+.07x+%2B+40\"$
\n" ); document.write( " $\"160+-+.08x+=+.07x+%2B+40\"$
\n" ); document.write( " $\".15x+=+120\"$
\n" ); document.write( " $\"x+=+800\"$
\n" ); document.write( " $\"2000+-+x+=+1200\"$
\n" ); document.write( "$800 was invested @ 7% and $1200 was invested @ 8% \n" ); document.write( "

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