document.write( "Question 161569: In 1/4 of an hour more time ,Jack , riding a bicycle at 12 mph, rode 6 mies farther than Tom, who was riding his bycycle at 10 mph. How long did Jack ride? \n" ); document.write( "
Algebra.Com's Answer #119041 by Alan3354(69443)\"\" \"About 
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In 1/4 of an hour more time ,Jack , riding a bicycle at 12 mph, rode 6 mies farther than Tom, who was riding his bycycle at 10 mph. How long did Jack ride?
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\n" ); document.write( "J = the distance Jack rode
\n" ); document.write( "M = the distance Tom rode (T might be confused with t for time)
\n" ); document.write( "t = the time Tom rode
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\n" ); document.write( "distance = rate x time
\n" ); document.write( "J = 12*(t + 1/4) (Jack rode 1/4 hr longer than Tom)
\n" ); document.write( "M = 10t
\n" ); document.write( "J = M + 6 (Jack rode 6 miles farther)
\n" ); document.write( "Sub for M
\n" ); document.write( "J = 10t + 6
\n" ); document.write( "J = 12*(t + 1/4) 1st eqn
\n" ); document.write( "10t + 6 = 12*(t + 1/4)
\n" ); document.write( "10t + 6 = 12t + 3
\n" ); document.write( "2t = 3
\n" ); document.write( "t = 1.5 hours
\n" ); document.write( "Jack rode 1/4 hour longer, = 1.75 hours or 1 hour 45 minutes.
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