document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161533>Question 161533</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A store owner has 12 pounds of pasta worth 70 cents a pound. She wants to mix it with pasta worth 45 cents a pound so that the total mixture can be sold for 55 cents a pound ( without any gain or loss). How much of the 45 cent pasta must she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118999 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118999\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .70*12+.45x=.55(12+x)<BR>\n" );
document.write( "8.4+.45x=6.6+.55x<BR>\n" );
document.write( ".45x-.55x=6.6-8.4<BR>\n" );
document.write( ".1x=1.8<BR>\n" );
document.write( "x=1.8/.1<BR>\n" );
document.write( "x=18 pounds of the $.45 pasta is needed.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".70*12+.45*18=.55(12+18)<BR>\n" );
document.write( "8.4+8.1=.55*30<BR>\n" );
document.write( "16.5=16.5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );