document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161518>Question 161518</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a worksheet and have two questions for you.  I am totally lost.\r<BR>\n" );
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document.write( "1.  Solve 3+2(1-x)>6 or 2x+14< or eual to 8.  Graph the solution set on a number line.  For this one one of the solutions I came up with is x < or equal to 11.  Not sure on the other one.\r<BR>\n" );
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document.write( "2.  Solve 3+ absolute value 2y-1 absolute value > or equal to 1.  Graph the solution set on a number line.\r<BR>\n" );
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document.write( "Please help..<BR>\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118997 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i solve first one as follows:<BR>\n" );
document.write( "3 + 2*(1-x) > 6<BR>\n" );
document.write( "removing parentheses<BR>\n" );
document.write( "3 + 2 - 2*x > 6<BR>\n" );
document.write( "adding 2*x to both sides and subtracting 6 from both sides gets<BR>\n" );
document.write( "3 + 2 - 6 > 2*x<BR>\n" );
document.write( "which becomes<BR>\n" );
document.write( "5 - 6 > 2*x<BR>\n" );
document.write( "which becomes<BR>\n" );
document.write( "-1 > 2*x<BR>\n" );
document.write( "subtracting 2*x from both sides and adding 1 to both sides and the equation becomes<BR>\n" );
document.write( "-2*x > 1<BR>\n" );
document.write( "multiplying both sides by -1 and the equation becomes<BR>\n" );
document.write( "2*x < -1 (note reversal of inequality.<BR>\n" );
document.write( "dividing both sides by 2 and equation becomes<BR>\n" );
document.write( "x < -1/2<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "i solve second one as follows.<BR>\n" );
document.write( "2*x + 14 <= 8<BR>\n" );
document.write( "subtracting 14 from both sides and it becomes<BR>\n" );
document.write( "2*x <= 8 - 14<BR>\n" );
document.write( "which becomes<BR>\n" );
document.write( "2*x <= -6<BR>\n" );
document.write( "dividing both sides by 2 and it becomes<BR>\n" );
document.write( "x <= -3<BR>\n" );
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document.write( "third one is a little confusing but i'll assume you mean<BR>\n" );
document.write( "3 + |2*y-1| >= 1<BR>\n" );
document.write( "subtracting 3 from both sides and the equation becomes<BR>\n" );
document.write( "|2*y-1| >= -2<BR>\n" );
document.write( "which doesn't make a lot of sense because the absolute value of anything will always be greater than 0, let alone -2.<BR>\n" );
document.write( "i can't really solve this part because i don't understand the question very well.<BR>\n" );
document.write( "resubmit this one if i got it wrong.<BR>\n" );
document.write( "if i got it right, then <BR>\n" );
document.write( "|2*y-1| >= -2<BR>\n" );
document.write( "is your answer and it will be valid for any value of y and the lowest value of |2*y-1| will be 0.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "back to the first two.<BR>\n" );
document.write( "we have 2 equations.<BR>\n" );
document.write( "first one is<BR>\n" );
document.write( "x < -1/2<BR>\n" );
document.write( "second one is<BR>\n" );
document.write( "x <= -3<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "i don't know if i can draw a number line good enough, but here's an attempt.\r<BR>\n" );
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document.write( "-----------------------------------------------------------------------------<BR>\n" );
document.write( "                 -3             -1/2  0   1/2           3<BR>\n" );
document.write( "-----------------------------------------------------------------------------<BR>\n" );
document.write( "---------------------------------|<BR>\n" );
document.write( "x is to the left up to but not including -1/2 for the first equation.\r<BR>\n" );
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document.write( "-----------------------------------------------------------------------------<BR>\n" );
document.write( "                 -3             -1/2  0   1/2           3<BR>\n" );
document.write( "-----------------------------------------------------------------------------<BR>\n" );
document.write( "------------------|<BR>\n" );
document.write( "x is to the left up to and including -3 for the second equation.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );