document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161499>Question 161499</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The larger of two numbers is 11 more than twice the smaller. The sum of the numbers is 1 less than seven times smaller. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118959 by </B><A HREF=/tutors/aboutme.mpl?userid=gonzo><B>gonzo(654)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gonzo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L = larger number<BR>\n" );
document.write( "S = smaller number<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "L = 2*S + 11<BR>\n" );
document.write( "L + S = 7 * S - 1<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "substituting for L in the second equation by using the equality in the first equation, we get<BR>\n" );
document.write( "(2*S + 11) + S = 7*S - 1<BR>\n" );
document.write( "removing parentheses, we get<BR>\n" );
document.write( "2*S + 11 + S = 7*S - 1<BR>\n" );
document.write( "combining like terms, we get<BR>\n" );
document.write( "3*S + 11 = 7*S - 1<BR>\n" );
document.write( "subtracting 3*S from both sides of the equation, we get<BR>\n" );
document.write( "11 = 7*S - 1 - 3*S<BR>\n" );
document.write( "adding 1 to both sides of the equation, we get<BR>\n" );
document.write( "11 + 1 = 7*S - 3*S<BR>\n" );
document.write( "combining like terms, we get<BR>\n" );
document.write( "12 = 4*S<BR>\n" );
document.write( "dividing both side of equation by 4, we get<BR>\n" );
document.write( "3 = S<BR>\n" );
document.write( "which is the same as<BR>\n" );
document.write( "S = 3<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "substituting for S in the first equation, we get<BR>\n" );
document.write( "first equation:<BR>\n" );
document.write( "L = 2*S + 11 <BR>\n" );
document.write( "L = 2*3 + 11<BR>\n" );
document.write( "L = 6 + 11<BR>\n" );
document.write( "L = 17<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "substituting for S and L in the second equation, we get<BR>\n" );
document.write( "L + S = 7*S - 1<BR>\n" );
document.write( "17 + 3 = 7*3 - 1<BR>\n" );
document.write( "20 = 21 - 1<BR>\n" );
document.write( "20 = 20<BR>\n" );
document.write( "answer is correct<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "answer is:<BR>\n" );
document.write( "L = 17<BR>\n" );
document.write( "S = 3<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );