document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22010>Question 22010</A>: <I><SPAN STYLE=\"word-break: break-all;\"> name the variable you would solve for first: 3x-y=-9;2x+4y=8\r<BR>\n" );
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document.write( "p.s. this is using the substitution method </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11893 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To use the substitution method, you must solve for one variable in one of the equations in terms of the other variable.  The easiest one in htese would be to solve for y in the first equation.  Since it's coefficient is either 1 or -1, solving for this variable will not end up with horrible fractions to substitute into the other equation.\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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