document.write( "Question 161445This question is from textbook Introductory Algebra
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document.write( ": Find two consectutive intergers such that the square of the sum of the two intergers is 11 more than the smaller interger.\r
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document.write( "I tried to set this up like : x(x+1)=(x+x+1)+11\r
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document.write( "and the answer is -2,-1.\r
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document.write( "but of course we have to show our work ..... \n" );
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Algebra.Com's Answer #118915 by scott8148(6628) You can put this solution on YOUR website! \" the square of the sum of the two intergers is 11 more than the smaller interger\" \n" ); document.write( "__ (x+x+1)^2=x+11 __ (2x+1)^2=x+11 __ 4x^2+3x-10=0 __ factoring __ (4x-5)(x+2)=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4x-5=0 __ x=5/4 __ not an integer\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x+2=0 __ x=-2 __ x+1=-1 \n" ); document.write( " |