document.write( "Question 161436: Can you please help me with this equation?
\n" ); document.write( "3x^2 = 2x+5
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\n" ); document.write( "So far I got:
\n" ); document.write( "3x^2= 2x+5
\n" ); document.write( "-3x^2 -3x^2\r
\n" ); document.write( "\n" ); document.write( "-3x^2 +2x+5=0
\n" ); document.write( "X=-(2) ± (sqr of 2^2 - 4(-3)(5) ) / 2(-3)
\n" ); document.write( "X= -2 ± (sqr of 4- -60) / -6
\n" ); document.write( "X= -2 ± (sqr of 64) / -6
\n" ); document.write( "X= -2 ± (sqr of 8 )/ -6
\n" ); document.write( "X= -2 ± 2 (sqr of 2) /-6\r
\n" ); document.write( "\n" ); document.write( "I am unsure what to do after this, if anything at all. Can u show me step by step what to do and explain where I went wrong? I think I'm on the right track but it got tricky with the -6. Thank you so much for even considering my request.
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Algebra.Com's Answer #118904 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
3x^2=2x+5
\n" ); document.write( "3x^2-2x-5=0
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "x=(2+-sqrt[-2^2-4*3*-5])/2*3
\n" ); document.write( "x=(2+-sqrt[4+60])/6
\n" ); document.write( "x=(2+-sqrt64)/6
\n" ); document.write( "x=(2+-8)/6
\n" ); document.write( "x=(2+8)/6
\n" ); document.write( "x=10/6=5/3 answer.
\n" ); document.write( "x=(2-8)/6
\n" ); document.write( "x=-6/6
\n" ); document.write( "x=-1 answer.
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