document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2771>Question 2771</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the center (h,k) of the circle with the equation x^2+y^2-6y=7.<BR>\n" );
document.write( "(h,k)=(_,_)<BR>\n" );
document.write( "a. 0,9<BR>\n" );
document.write( "b.-3,9<BR>\n" );
document.write( "c.0,3<BR>\n" );
document.write( "d.9,16\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks for your help.......... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1189 by </B><A HREF=/tutors/aboutme.mpl?userid=kiru_khandelwal><B>kiru_khandelwal(79)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kiru_khandelwal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1189\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find centre of the circle with equation x^2+y^2-6y = 7<BR>\n" );
document.write( "Convert the equation to the form <BR>\n" );
document.write( "(x-h)^2 + (y-k)^2 = r^2 <BR>\n" );
document.write( "where h and k are coordinates of the centre of the circle and r is the radiys of the circie<BR>\n" );
document.write( "so x^2 + Y^2 -6y +9 = 7+9<BR>\n" );
document.write( "=> x^2 +(y-3)^2 = 16<BR>\n" );
document.write( "=> (x-0)^2 + (y-3)^2 = 4^2<BR>\n" );
document.write( "so centre of the circle is (0,3) and radius is 4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );