document.write( "Question 161427: how do you solve:
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document.write( " the length of a rectangle is 2 less than 4 times the width and the perimeter is 56? \n" );
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Algebra.Com's Answer #118890 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "the length of a rectangle is 2 less than 4 times the width and the perimeter is 56? \n" ); document.write( ". \n" ); document.write( "Let w = width of rectangle \n" ); document.write( "then from \"the length of a rectangle is 2 less than 4 times the width\" \n" ); document.write( "4w-2 = length of rectangle \n" ); document.write( ". \n" ); document.write( "Perimeter is 2(L + W) \n" ); document.write( "2[(4w-2) + w] = 56 \n" ); document.write( "2[5w-2] = 56 \n" ); document.write( "10w-4 = 56 \n" ); document.write( "10w = 60 \n" ); document.write( "w = 6 (width) \n" ); document.write( ". \n" ); document.write( "length: \n" ); document.write( "4w-2 = 4(6)-2 = 24-2 = 22 (length) \n" ); document.write( " |