document.write( "Question 161427: how do you solve:
\n" ); document.write( " the length of a rectangle is 2 less than 4 times the width and the perimeter is 56?
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Algebra.Com's Answer #118889 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
2L+2W=PERIMETER
\n" ); document.write( "L=4W-2
\n" ); document.write( "2(4W-2)+2W=56
\n" ); document.write( "8W-4+2W=56
\n" ); document.write( "10W=56+4
\n" ); document.write( "10W=60
\n" ); document.write( "W=60/10
\n" ); document.write( "W=6 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=4*6-2
\n" ); document.write( "L=24-2
\n" ); document.write( "L=22 ANSWER FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "2*22+2*6=56
\n" ); document.write( "44+12=56
\n" ); document.write( "56=56
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