document.write( "Question 161427: how do you solve:
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document.write( " the length of a rectangle is 2 less than 4 times the width and the perimeter is 56? \n" );
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Algebra.Com's Answer #118889 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! 2L+2W=PERIMETER \n" ); document.write( "L=4W-2 \n" ); document.write( "2(4W-2)+2W=56 \n" ); document.write( "8W-4+2W=56 \n" ); document.write( "10W=56+4 \n" ); document.write( "10W=60 \n" ); document.write( "W=60/10 \n" ); document.write( "W=6 ANSWER FOR THE WIDTH. \n" ); document.write( "L=4*6-2 \n" ); document.write( "L=24-2 \n" ); document.write( "L=22 ANSWER FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*22+2*6=56 \n" ); document.write( "44+12=56 \n" ); document.write( "56=56 \n" ); document.write( " \n" ); document.write( " |