document.write( "Question 161351: Complete the square for 2x2 + 5x – 1 = 0 \n" ); document.write( "
Algebra.Com's Answer #118857 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B5x-1\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28x%5E2%2B%285%2F2%29x-1%2F2%29\" Factor out the \"x%5E2\" coefficient \"2\". This step is very important: the \"x%5E2\" coefficient must be equal to 1.\r
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\n" ); document.write( "\n" ); document.write( "Take half of the \"x\" coefficient \"5%2F2\" to get \"5%2F4\". In other words, \"%281%2F2%29%285%2F2%29=5%2F4\".\r
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\n" ); document.write( "\n" ); document.write( "Now square \"5%2F4\" to get \"25%2F16\". In other words, \"%285%2F4%29%5E2=%285%2F4%29%285%2F4%29=25%2F16\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%28x%5E2%2B%285%2F2%29x%2Bhighlight%2825%2F16-25%2F16%29-1%2F2%29\" Now add and subtract \"25%2F16\" inside the parenthesis. Make sure to place this after the \"x\" term. Notice how \"25%2F16-25%2F16=0\". So the expression is not changed.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28%28x%5E2%2B%285%2F2%29x%2B25%2F16%29-25%2F16-1%2F2%29\" Group the first three terms.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28%28x%2B5%2F4%29%5E2-25%2F16-1%2F2%29\" Factor \"x%5E2%2B%285%2F2%29x%2B25%2F16\" to get \"%28x%2B5%2F4%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"2%28%28x%2B5%2F4%29%5E2-33%2F16%29\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28x%2B5%2F4%29%5E2%2B2%28-33%2F16%29\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"2%28x%2B5%2F4%29%5E2-33%2F8\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "So after completing the square, \"2x%5E2%2B5x-1\" transforms to \"2%28x%2B5%2F4%29%5E2-33%2F8\". So \"2x%5E2%2B5x-1=2%28x%2B5%2F4%29%5E2-33%2F8\".\r
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\n" ); document.write( "\n" ); document.write( "So \"2x%5E2%2B5x-1=0\" is equivalent to \"2%28x%2B5%2F4%29%5E2-33%2F8=0\".\r
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