document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161347>Question 161347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cyclists start from the same point and ride in opposite deirections. ONe cyclist rides twice as fast as the the other. In 3 hours they are 81 miles apart. Find the rate of each cyclist. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118853 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118853\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x+3*2x=81<BR>\n" );
document.write( "3x+6x=81<BR>\n" );
document.write( "9x=81<BR>\n" );
document.write( "x=81/9<BR>\n" );
document.write( "x=9 mph for the slower biker.<BR>\n" );
document.write( "2*9=18 mph for the faster biker.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "3*9+6*9=81<BR>\n" );
document.write( "27+54=81<BR>\n" );
document.write( "81=81 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );