document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161255>Question 161255</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Question 1.<BR>\n" );
document.write( "One printing machine works twice as fast as another. When both machines are use, they can print a magazine in 3 h. How many hours would each machine require to do the job alone.\r<BR>\n" );
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document.write( "Question 2. I takes my father 3 h to plow our cornfield with his new tractor. Using the old tractor it takes me 5 h. If we both plow for 1 hr before i go to school, how long will it take him to finish plowing. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118849 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118849\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1) each machine does some fraction of the job __ one machine's fraction is twice as large as the other machine's<BR>\n" );
document.write( "__ 3/x+3/2x=1 __ multiplying by 2x __ 6+3=2x __ 4.5=x\r<BR>\n" );
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document.write( "2) in the hour before school, you plow 1/5 (3/15) of the field and your father plows 1/3 (5/15)<BR>\n" );
document.write( "__ 7/15 remains to be plowed __ 7/15 * 3 = 21/15 __ 1 hr 24 min </SPAN>\n" );
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