document.write( "Question 161321This question is from textbook Algebra
\n" ); document.write( ": Kwan hiked uphill at 4km/h and back down at 6km/h. His total hiking time was 3h. how long did the trip up the hill take him? \n" ); document.write( "
Algebra.Com's Answer #118834 by ankor@dixie-net.com(22740)\"\" \"About 
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Kwan hiked uphill at 4km/h and back down at 6km/h. His total hiking time was 3h. how long did the trip up the hill take him?
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\n" ); document.write( "Let t = time to hike up the hill
\n" ); document.write( "It states that the total time time up & down is 3 hr; therefore
\n" ); document.write( "(3-t) = time down the hill
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\n" ); document.write( "The distance up and down is the same. Write a distance equation from this fact:
\n" ); document.write( "Dist = speed * time
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\n" ); document.write( "4t = 6(3-t)
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\n" ); document.write( "4t = 18 - 6t
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\n" ); document.write( "4t + 6t = 18
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\n" ); document.write( "10t = 18
\n" ); document.write( "t = \"18%2F10\"
\n" ); document.write( "t = 1.8 hrs to hike up the hill. 1 hr 48 min (.8*60)
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\n" ); document.write( "Check solution: Down hill: 3 - 1.8 = 1.2 hrs
\n" ); document.write( "6*1.2 = 7.2 mi
\n" ); document.write( "4*1.8 = 7.2 mi \n" ); document.write( "
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