document.write( "Question 161327: I need help please!!! I can't figure this out at all.
\n" ); document.write( "While finding the amount of seed to plant his three suare wheat fields, Hank observed that the side of one field was 1 kilometer longer than the side of the smallest field and that the side of the largest field was 3 kilometers longer than the side of the smallest field. If the total area of the three fields is 38 square kilometers, then what is the area of each field?
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Algebra.Com's Answer #118820 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
Let x = length of side of smallest field
\n" ); document.write( "then because \"the side of one field was 1 kilometer longer than the side of the smallest field\"
\n" ); document.write( "x+1 = length of one field
\n" ); document.write( "and because \"the largest field was 3 kilometers longer than the side of the smallest field.\"
\n" ); document.write( "x+3 = length of largest field
\n" ); document.write( ".
\n" ); document.write( "Area of each field is side^2:
\n" ); document.write( "x^2 + (x+1)^2 + (x+3)^2 = 38
\n" ); document.write( "expanding through FOIL:
\n" ); document.write( "x^2 + x^2+2x+1 + x^2+6x+9 = 38
\n" ); document.write( "combining like-terms:
\n" ); document.write( "3x^2 + 8x + 10 = 38
\n" ); document.write( "3x^2 + 8x - 28 = 0
\n" ); document.write( "(3x+14)(x-2) = 0
\n" ); document.write( "x = {-14/3, 2}
\n" ); document.write( ".
\n" ); document.write( "We can toss out the negative solution leaving us with:
\n" ); document.write( "x = 2 km
\n" ); document.write( "x^2 = 4 sq km (smallest field)
\n" ); document.write( ".
\n" ); document.write( "(x+1)^2 = x^2+2x+1 = 2^2+2(2)+1 = 4+4+1 = 9 sq km (one field)
\n" ); document.write( ".
\n" ); document.write( "(x+3)^2 = x^2+6x+9 = 2^2+6(2)+9 = 4+12+9 = 25 sq km (largest field)
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\n" ); document.write( "Answer:
\n" ); document.write( "4 square kilometers
\n" ); document.write( "9 square kilometers
\n" ); document.write( "25 square kilometers
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