document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161313>Question 161313</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you please help me solve this equation?  3/4x-5=2/3x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118808 by </B><A HREF=/tutors/aboutme.mpl?userid=schrammbledeggs><B>schrammbledeggs(41)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=schrammbledeggs><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118808\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/4x - 5 = 2/3x\r<BR>\n" );
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document.write( "To solve this problem let's find the lowest common denominator of the fractions...\r<BR>\n" );
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document.write( "The denominators are 4 and 3...meaning the lowest common denominator is 12...we find that by multiplying those two numbers together...\r<BR>\n" );
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document.write( "So since we multiplied the 4 and 3 in the denominators to get 12 we must do the same operation to the numerators...\r<BR>\n" );
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document.write( "For 3/4...we multiplied the 4 by 3 so we must multiply the 3 by 3...the new fraction is 9/12.\r<BR>\n" );
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document.write( "For 2/3...we multiplied the 3 by 4 so we must multiply the 2 by 4...the new fraction is 8/12...\r<BR>\n" );
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document.write( "So our new equation is:\r<BR>\n" );
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document.write( "9/12x - 5 = 8/12x\r<BR>\n" );
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document.write( "Subtract 8/12x from both sides...\r<BR>\n" );
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document.write( "9/12x - 8/12x - 5 = 0\r<BR>\n" );
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document.write( "Add 5 to both sides...\r<BR>\n" );
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document.write( "1/12x -5 + 5 = 0 + 5<BR>\n" );
document.write( "1/12x = 5\r<BR>\n" );
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document.write( "Now multiply by 12 on both sides to get x by itself...\r<BR>\n" );
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document.write( "x = 5 * 12\r<BR>\n" );
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document.write( "x = 60\r<BR>\n" );
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