document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161295>Question 161295</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dee has 6 steel balls of equal mass.  If he puts 5 in one pan, it equals teh mas of one in a 100 gram box.  what is teh weight of each ball? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118807 by </B><A HREF=/tutors/aboutme.mpl?userid=schrammbledeggs><B>schrammbledeggs(41)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=schrammbledeggs><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So an algebraic equation for this problem would be:\r<BR>\n" );
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document.write( "Let x = mass of a steel ball\r<BR>\n" );
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document.write( "5x = x + 100\r<BR>\n" );
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document.write( "Subtract x from both sides...\r<BR>\n" );
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document.write( "5x - x = x + 100 - x\r<BR>\n" );
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document.write( "4x = 100\r<BR>\n" );
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document.write( "Divide 4 from both sides...\r<BR>\n" );
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document.write( "x = 100/4\r<BR>\n" );
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document.write( "x = 25 grams per ball\r<BR>\n" );
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document.write( ":) </SPAN>\n" );
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