document.write( "Question 161302: if v=4+2f, solve 3v+2f=28 for f \n" ); document.write( "
Algebra.Com's Answer #118794 by schrammbledeggs(41)\"\" \"About 
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Substitution is the key to solving this problem.\r
\n" ); document.write( "\n" ); document.write( "We're given V = 4 + 2F and are asked to solve 3V + 2F = 28\r
\n" ); document.write( "\n" ); document.write( "So what we'll do is plug the value of V into the equation.\r
\n" ); document.write( "\n" ); document.write( "3 (4 + 2F) + 2F = 28\r
\n" ); document.write( "\n" ); document.write( "Now we distribute the 3.\r
\n" ); document.write( "\n" ); document.write( "(3 x 4) + (3 X 2F) + 2F = 28\r
\n" ); document.write( "\n" ); document.write( "12 + 6F + 2F = 28\r
\n" ); document.write( "\n" ); document.write( "Now we combine like terms (the F's)\r
\n" ); document.write( "\n" ); document.write( "12 + 8F = 28\r
\n" ); document.write( "\n" ); document.write( "Subtract 12 from both sides\r
\n" ); document.write( "\n" ); document.write( "12 + 8F - 12 = 28 - 12\r
\n" ); document.write( "\n" ); document.write( "8F = 16\r
\n" ); document.write( "\n" ); document.write( "Divide both sides by 8\r
\n" ); document.write( "\n" ); document.write( "8F/8 = 16/8\r
\n" ); document.write( "\n" ); document.write( "F = 2\r
\n" ); document.write( "\n" ); document.write( ":) \n" ); document.write( "
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