document.write( "Question 161270: Cathy traveled by boat 4 miles upstream to fish. Because of the 5mph current it took her 40 minutes longer to get there than to return. How fast will her boat go in still water? \n" ); document.write( "
Algebra.Com's Answer #118792 by ankor@dixie-net.com(22740)\"\" \"About 
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Cathy traveled by boat 4 miles upstream to fish. Because of the 5mph current it took her 40 minutes longer to get there than to return. How fast will her boat go in still water?
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\n" ); document.write( "Let s = speed in still water
\n" ); document.write( "then
\n" ); document.write( "(s+5) = speed downstream
\n" ); document.write( "and
\n" ); document.write( "(x-5) = speed upstream
\n" ); document.write( ":
\n" ); document.write( "Change 40 min to hrs: 40 min = \"2%2F3\" hr
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\n" ); document.write( "Write time equation; time = \"dist%2Fspeed\"
\n" ); document.write( ":
\n" ); document.write( "Downstream time + 2/3 hr = upstream time
\n" ); document.write( "\"4%2F%28%28s%2B5%29%29\" + \"2%2F3\" = \"4%2F%28%28s-5%29%29\"
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by 3(s-5)(s+5) to get rid of the denominators
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\n" ); document.write( "4(3(s-5)) + 2(s-5)(s+5) = 4(3(s+5))
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\n" ); document.write( "12s - 60 + 2(s^2 - 25) = 12s + 60
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\n" ); document.write( "12s - 60 + 2s^2 - 50 = 12s + 60
\n" ); document.write( "Combine like terms on the left
\n" ); document.write( "2s^2 + 12s - 12s - 60 - 50 - 60 = 0
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\n" ); document.write( "2s^2 - 170 = 0
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\n" ); document.write( "2s^2 = +170
\n" ); document.write( "s^2 = \"170%2F2\"
\n" ); document.write( "s^2 = 85
\n" ); document.write( "s = \"sqrt%2885%29\"
\n" ); document.write( "s = 9.22 mph in still water
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\n" ); document.write( "Check solution on a calc:
\n" ); document.write( "4/14.22 + .67 = .95
\n" ); document.write( "4/4.22 = .95
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