document.write( "Question 161287: Find the first 10 terms of each sequence:
\n" ); document.write( "An=An-1+2xAn-2
\n" ); document.write( "A1 = 1 A2 = 5
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Algebra.Com's Answer #118776 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
I'll do the next few, you pick it up from there and do the rest. You are given
\n" ); document.write( "a[x] = a[x-1] + 2* a[x-2]
\n" ); document.write( "\"a%5B1%5D+=+1\"
\n" ); document.write( "\"a%5B2%5D+=+2\"\r
\n" ); document.write( "\n" ); document.write( "To find \"a%5B3%5D\"
\n" ); document.write( "a[x] = a[x-1] + 2*a[x-2]
\n" ); document.write( "a[3] = a[3-1] + 2*a[3-2]
\n" ); document.write( "\"a%5B3%5D+=+a%5B2%5D+%2B+2%2Aa%5B1%5D\"
\n" ); document.write( "\"a%5B3%5D+=+2+%2B+2%2A1\"
\n" ); document.write( "\"a%5B3%5D+=+4\"\r
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\n" ); document.write( "\n" ); document.write( "To find \"a%5B4%5D\"
\n" ); document.write( "a[x] = a[x-1] + 2*a[x-2]
\n" ); document.write( "a[4] = a[4-1] + 2*a[4-2]
\n" ); document.write( "\"a%5B4%5D+=+a%5B3%5D+%2B+2%2Aa%5B2%5D\"
\n" ); document.write( "\"a%5B4%5D+=+4+%2B+2%2A2\"
\n" ); document.write( "\"a%5B4%5D+=+8\"\r
\n" ); document.write( "\n" ); document.write( "and so on. On each iteration, you bump the number s up by one. You then need the previous two answers in order to solve for the new x.\r
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