document.write( "Question 161239This question is from textbook Algebra 2
\n" ); document.write( ": John and Jim are going on a bike ride. On the trip to Mill Park, they ride at an average of 8 mph on a route that is 4 miles less than the route on the return. They travel 7 mph on the return trip. If it takes them one hour longer to return than to go, how much total time do they spend riding their bicycles? \n" ); document.write( "
Algebra.Com's Answer #118768 by ankor@dixie-net.com(22740)\"\" \"About 
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they ride at an average of 8 mph on a route that is 4 miles less than the route on the return. They travel 7 mph on the return trip. If it takes them one hour longer to return than to go, how much total time do they spend riding their bicycles?
\n" ); document.write( ":
\n" ); document.write( "Let t = travel time on outbound trip
\n" ); document.write( "then
\n" ); document.write( "(t+1) = travel time on the return trip
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation: Dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "Out bound dist + 4 mi = return dist
\n" ); document.write( "8t + 4 = 7(t+1)
\n" ); document.write( "8t + 4 = 7t + 7
\n" ); document.write( "8t - 7t = 7 - 4
\n" ); document.write( "t = 3 hrs
\n" ); document.write( "then the return trip time:
\n" ); document.write( "3 + 1 = 4 hrs
\n" ); document.write( ":
\n" ); document.write( "Total time in the bikes: 4 + 3 = 7 hrs
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check solution by finding the dist:
\n" ); document.write( "out: 3*8 = 24 mi
\n" ); document.write( "back: 4*7 = 28 mi
\n" ); document.write( "------------------
\n" ); document.write( "difference = 4 mi \n" ); document.write( "
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