document.write( "Question 161172: The radiator of a car holds 16 quarts of liquid of which 8 are antifreeze. The radiator has a leak and loses 2 quarts of liquid each week. Every week, 2 quarts of water are added. After 3 weeks how much antifreeze is left in the radiator? (explain your reasoning, just the answer is not sufficient).
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Algebra.Com's Answer #118747 by ankor@dixie-net.com(22740)\"\" \"About 
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The radiator of a car holds 16 quarts of liquid of which 8 are antifreeze. The radiator has a leak and loses 2 quarts of liquid each week. Every week, 2 quarts of water are added. After 3 weeks how much antifreeze is left in the radiator?
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\n" ); document.write( "Let x = fractional amt of antifreeze after 2 qts leak out & 2 qt water added
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\n" ); document.write( "Week 1:
\n" ); document.write( "\"1%2F2\"(16-2) = 16x (2 qts of water added to make it 16 again)
\n" ); document.write( "\"1%2F2\"(14) = 16x
\n" ); document.write( "7 = 16x
\n" ); document.write( "x = \"7%2F16\";
\n" ); document.write( "Therefore: \"7%2F16\"*16 = 7 qts, of antifreeze after week 1
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\n" ); document.write( "Week 2;
\n" ); document.write( "\"7%2F16\"(16-2) = 16x
\n" ); document.write( "\"7%2F16\"14 = 16x
\n" ); document.write( "\"98%2F16\" = 16x
\n" ); document.write( "x = \"98%2F16\"*\"1%2F16\"
\n" ); document.write( "x = \"98%2F256\";
\n" ); document.write( "Therefore: \"98%2F256\"*16 = 6.125 qts of antifreeze after week 2
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\n" ); document.write( "Week 3:
\n" ); document.write( "\"98%2F256\"(16-2) = 16x
\n" ); document.write( "\"98%2F256\"(14) = 16x
\n" ); document.write( "\"1372%2F256\" = 16x
\n" ); document.write( "x = \"1372%2F256\" * \"1%2F16\"
\n" ); document.write( "x = \"1372%2F4096\";
\n" ); document.write( "therefore: \"1372%2F4096\"*16 = 5.34 qts of antifreeze after week 3
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\n" ); document.write( "Hope this makes sense.
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