document.write( "Question 161213: solve this problem please...what is the next sequence-- 1,2,6,42,1806,... \n" ); document.write( "
Algebra.Com's Answer #118744 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
When the answers are not 'obvious' I try a few things to whiitle down what I think will or 'work.\r
\n" ); document.write( "\n" ); document.write( "This one does not look arithmetic. The numbers climb too fast. So it 'feels' like we need to be multiplying by something or doing something exponential.\r
\n" ); document.write( "\n" ); document.write( "Start with the last two numbers \"1806%2F42\" = \"43\" hmmm, 43 is just one more than 42.
\n" ); document.write( "Let's do \"42%2F6\"=\"7\" hey! again we get a number one greater than the lower number in the pair. \r
\n" ); document.write( "\n" ); document.write( "Does that work for the entire sequence? In this case, yes\r
\n" ); document.write( "\n" ); document.write( "Each successive number is the previous number times (the previous number+1)\r
\n" ); document.write( "\n" ); document.write( "I wish I could tell you there is magic formula here. But I haven;t found one. It is more a matter of doing a few and getting a feel for what to try if something just doesn;t jump rite out at you
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