document.write( "Question 161201: Solve by the elimination method.\r
\n" ); document.write( "\n" ); document.write( "0.05x+0.25y=44
\n" ); document.write( "0.15x+0.05y=48\r
\n" ); document.write( "\n" ); document.write( "What is the solution of the system?
\n" ); document.write( "

Algebra.Com's Answer #118743 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
\"0.05x%2B0.25y=44\"
\n" ); document.write( "\"0.15x%2B0.05y=48\"\r
\n" ); document.write( "\n" ); document.write( "Multiply the first equation by 3 to get
\n" ); document.write( "\"0.15x%2B0.75y=+132\"
\n" ); document.write( "\"0.15x%2B0.05y=48\" subtract
\n" ); document.write( "-----------------------
\n" ); document.write( " \"0.70y+=+84+\"
\n" ); document.write( "\"y+=+120\"
\n" ); document.write( "\"0.05x%2B0.25%28120%29+=+44\"
\n" ); document.write( "\"0.05x+=+14\"
\n" ); document.write( "\"x+=+280\"
\n" ); document.write( "
\n" );