document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161150>Question 161150</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618250182/algebrahomeworkh>Algebra 1</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that for some bridge the expansion gap is 16.8mm wide at 10 degrees C and decreases by .37mm for every 1 degree C rise in temperature.\r<BR>\n" );
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document.write( "The book gives us the answers but we want to understand what is going on.\r<BR>\n" );
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document.write( "Question 57 - The temperature rises to t degrees C.  Write expressions for the temperature rise, the decrease in the width of the gap, and the new width of the gap.\r<BR>\n" );
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document.write( "Question 58 - Use the expressions from Exercise 57.  Write and solve an equation to find the temperature at which the gap decreases to 9.4mm.\r<BR>\n" );
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document.write( "Please help us to understand these two problems...thank you so much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118730 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118730\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 57) the temperature rise is the increase from 10º, so the new temperature (t) MINUS the 10º gives the rise __ t-10\r<BR>\n" );
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document.write( "the decrease in the gap is .37mm for each degree of temperature rise, so the decrease would be .37(t-10)\r<BR>\n" );
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document.write( "the new width is the old width MINUS the decrease __ 16.8-[.37(t-10)]\r<BR>\n" );
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document.write( "58) 9.4=16.8-[.37(t-10)] __ 9.4=16.8-.37t+3.7 __ subtracting 16.8+3.7 __ -11.1=-.37t\r<BR>\n" );
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document.write( "dividing by -.37 __ 30=t </SPAN>\n" );
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