document.write( "Question 161177: Mrs.Johnson is 3 times as old as her son.Ten years ago she was 5 times as old as her son was then.Find each of their ages. \n" ); document.write( "

Algebra.Com's Answer #118717 by jojo14344(1513) $\"\"$ $\"About$

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\n" ); document.write( "Son's age= $\"x\"$
\n" ); document.write( "Mrs.Jonhson's age= $\"3x\"$ , 3 times Son's age
\n" ); document.write( "Condition: 10 yrs ago, she was 5 times as old as her son.
\n" ); document.write( " $\"5%28x-10%29=3x-10\"$
\n" ); document.write( " $\"5x-50=3x-10\"$
\n" ); document.write( " $\"5x-3x=50-10\"$
\n" ); document.write( " $\"2x=40\"$ ----> $\"cross%282%29x%2Fcross%282%29=cross%2840%2920%2Fcross%282%29\"$
\n" ); document.write( " $\"x=20yrs\"$ , age of Son
\n" ); document.write( " $\"3%2A20=60yrs\"$ , age of Mrs.Johnson
\n" ); document.write( "check via the condition
\n" ); document.write( "Age of her son 10 yrs ago: 20-10=10yrs
\n" ); document.write( "Age of Mrs.Johnson 10 yrs ago: 60-10=50 yrs ---> 5 times the age of her son $\"5%2A10=50\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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