document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=161040>Question 161040</A>: <I><SPAN STYLE=\"word-break: break-all;\"> CAN SOMEONE PLEASE HELP ME WITH THIS PROBLEM:\r<BR>\n" );
document.write( "\n" );
document.write( "The length a spring is stretched from its natural length with work, W foot-pounds, given by L = checksign (2W/k) where k is a constant for the given spring. If a certain spring has a constant of 76.4, and the spring is to be stretched 3.6 feet from its natural length, how much work will be necessary? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #118694 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=118694\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> squaring __ L^2=2W/k __ multiplying by k and dividing by 2 __ (kL^2)/2=W\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "76.4 * 3.6^2 /2 =W __ 495=W (approx) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );