document.write( "Question 161098: The perimeter of a rectangle is 100 m. The length is 8 m more than twice the width. Find the demensions.\r
\n" ); document.write( "\n" ); document.write( "What is the length? ______ m\r
\n" ); document.write( "\n" ); document.write( "What is the width? ______ m\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #118675 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Let W be the width. Let L be the length.
\n" ); document.write( "\"L+=+2W+%2B+8\"\r
\n" ); document.write( "\n" ); document.write( "\"Perimeter+=+2L+%2B+2W+\"
\n" ); document.write( "\"100+=+2%282W%2B8%29+%2B+2W+\"
\n" ); document.write( "\"100+=+4W+%2B+16+%2B+2W+\"
\n" ); document.write( "\"84+=+6W+\"
\n" ); document.write( "\"14+=+W+\"
\n" ); document.write( "\"L+=+2%2A14+%2B+8+\"
\n" ); document.write( "\"L+=+28+%2B+8\"
\n" ); document.write( "\"L+=+36\"
\n" ); document.write( "Does 36 + 36 + 14 + 14 = 100?\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );