document.write( "Question 161107This question is from textbook Thinking Mathematically
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document.write( ": A group of four men and five women. Three people are selected to attend a conference.
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document.write( "a. In how many ways can three people be selected from this group of nine?
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document.write( "b. In how many ways can three women be selected from the five women?
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document.write( "c. Find the probability that the selected group will consist of all women.
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document.write( "This is how I answered:
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document.write( " (a) 9!/(9-3)! 3! = 9*8*7*6*5*4*3*2*1/6*3*2*1 cancel out the 6 on the numerator and denominator = 504/6 = 84 This is the answere the book gave as well.
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document.write( " (b) 5!/(5-3)! 3! = 5*4*3*2*1/2*3*2*1 cancel out the 2 in the numeratoer and denominator = 60/6 = 10 agan, this is also the answer the book gives.
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document.write( " (c) this is where I am stuck I tried this 5!/(9-5)! 3! = 5*4*3*2*1/4*3*2*1 cancelling out the 4 in the numerator and the denominator which will leave you
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document.write( " with 5 as a numerator, but if we cancel out the 4 on the denominator that will leave us with 6 which is the wrong answer. The books states that the answer
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document.write( " should be 5/42.\r
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document.write( "If you can help me to understand how they come up with 5/42 for I would appreciate it. Thanks a million!\r
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document.write( "KiKi \n" );
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Algebra.Com's Answer #118672 by vleith(2983)![]() ![]() ![]() You can put this solution on YOUR website! You have a 5 in 9 chance of the first person being a woman. \n" ); document.write( "You then have a 4 in 8 chance of the second one being a woman. \n" ); document.write( "Finally, you have a 3 in 7 chance of the third person being a woman. \n" ); document.write( "So the chances are \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |