document.write( "Question 161020: Extreme hardship. Kim starts to walk 3 mi to school at 7:30 A.M. with a temperature of 0°F. Her brother Bryan starts at 7:45 A.M. on his bicycle, traveling 10 mph faster than Kim. If they get to school at the same time, then how fast is each one traveling? \n" ); document.write( "
Algebra.Com's Answer #118666 by ankor@dixie-net.com(22740)\"\" \"About 
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Kim starts to walk 3 mi to school at 7:30 A.M. with a temperature of 0°F. Her brother Bryan starts at 7:45 A.M. on his bicycle, traveling 10 mph faster than Kim. If they get to school at the same time, then how fast is each one traveling?
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\n" ); document.write( "Change 15 min to hrs: 15/60 = .25 hrs
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\n" ); document.write( "Let s = K's walking speed
\n" ); document.write( "then
\n" ); document.write( "(s+10) = B's biking speed
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\n" ); document.write( "Write a time equation: Time = \"dist%2Fspeed\"
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\n" ); document.write( "K's travel time = B's travel time + .25 hr
\n" ); document.write( "\"3%2Fs\" = \"3%2F%28%28s%2B10%29%29\" + .25
\n" ); document.write( ":
\n" ); document.write( "Multiply equation by t(t+10) to get rid of the denominator, results
\n" ); document.write( "3(s+10) = 3s + .25(s(s+10)
\n" ); document.write( ":
\n" ); document.write( "3s + 30 = 3s + .25s^2 + 2.5s
\n" ); document.write( "Arrange as a quadratic equation on the right
\n" ); document.write( "0 = .25s^2 + 2.5s + 3s - 3s - 30
\n" ); document.write( ":
\n" ); document.write( ".25s^2 + 2.5s - 30 = 0
\n" ); document.write( "Get rid of those decimals, mult equation by 4, results
\n" ); document.write( "s^2 + 10s - 120 = 0
\n" ); document.write( ":
\n" ); document.write( "Use the quadratic formula to solve for s:
\n" ); document.write( "\"s+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "In this equation a=1, b=10, c=-120
\n" ); document.write( "\"s+=+%28-10+%2B-+sqrt%2810%5E2+-+4%2A1%2A-120+%29%29%2F%282%2A1%29+\"
\n" ); document.write( ":
\n" ); document.write( "\"s+=+%28-10+%2B-+sqrt%28100+%2B+480+%29%29%2F%282%29+\"
\n" ); document.write( "solve this you should get a postive solution of:
\n" ); document.write( "s = 7.05 mph is K's walking speed
\n" ); document.write( "then
\n" ); document.write( "7.05 + 10 = 17.05 mph is B's biking speed
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\n" ); document.write( "Confirm this by finding the time of each
\n" ); document.write( "3/7.05 = .425 hrs or 25.5 min
\n" ); document.write( "3/17.05 = .176 hrs or 10.6 min
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\n" ); document.write( "Difference ~ 15 min
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