document.write( "Question 161020: Extreme hardship. Kim starts to walk 3 mi to school at 7:30 A.M. with a temperature of 0°F. Her brother Bryan starts at 7:45 A.M. on his bicycle, traveling 10 mph faster than Kim. If they get to school at the same time, then how fast is each one traveling? \n" ); document.write( "
Algebra.Com's Answer #118666 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Kim starts to walk 3 mi to school at 7:30 A.M. with a temperature of 0°F. Her brother Bryan starts at 7:45 A.M. on his bicycle, traveling 10 mph faster than Kim. If they get to school at the same time, then how fast is each one traveling? \n" ); document.write( ": \n" ); document.write( "Change 15 min to hrs: 15/60 = .25 hrs \n" ); document.write( ": \n" ); document.write( "Let s = K's walking speed \n" ); document.write( "then \n" ); document.write( "(s+10) = B's biking speed \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = \n" ); document.write( ": \n" ); document.write( "K's travel time = B's travel time + .25 hr \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply equation by t(t+10) to get rid of the denominator, results \n" ); document.write( "3(s+10) = 3s + .25(s(s+10) \n" ); document.write( ": \n" ); document.write( "3s + 30 = 3s + .25s^2 + 2.5s \n" ); document.write( "Arrange as a quadratic equation on the right \n" ); document.write( "0 = .25s^2 + 2.5s + 3s - 3s - 30 \n" ); document.write( ": \n" ); document.write( ".25s^2 + 2.5s - 30 = 0 \n" ); document.write( "Get rid of those decimals, mult equation by 4, results \n" ); document.write( "s^2 + 10s - 120 = 0 \n" ); document.write( ": \n" ); document.write( "Use the quadratic formula to solve for s: \n" ); document.write( " \n" ); document.write( "In this equation a=1, b=10, c=-120 \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "solve this you should get a postive solution of: \n" ); document.write( "s = 7.05 mph is K's walking speed \n" ); document.write( "then \n" ); document.write( "7.05 + 10 = 17.05 mph is B's biking speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this by finding the time of each \n" ); document.write( "3/7.05 = .425 hrs or 25.5 min \n" ); document.write( "3/17.05 = .176 hrs or 10.6 min \n" ); document.write( "--------------- \n" ); document.write( "Difference ~ 15 min \n" ); document.write( " \n" ); document.write( " |